Optimal. Leaf size=71 \[ \frac{(a+b x) \left (a^2+2 a b x+b^2 x^2\right )^p \, _2F_1\left (1,2 p+1;2 (p+1);-\frac{e (a+b x)}{b d-a e}\right )}{(2 p+1) (b d-a e)} \]
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Rubi [A] time = 0.0323544, antiderivative size = 71, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.077, Rules used = {646, 68} \[ \frac{(a+b x) \left (a^2+2 a b x+b^2 x^2\right )^p \, _2F_1\left (1,2 p+1;2 (p+1);-\frac{e (a+b x)}{b d-a e}\right )}{(2 p+1) (b d-a e)} \]
Antiderivative was successfully verified.
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Rule 646
Rule 68
Rubi steps
\begin{align*} \int \frac{\left (a^2+2 a b x+b^2 x^2\right )^p}{d+e x} \, dx &=\left (\left (a b+b^2 x\right )^{-2 p} \left (a^2+2 a b x+b^2 x^2\right )^p\right ) \int \frac{\left (a b+b^2 x\right )^{2 p}}{d+e x} \, dx\\ &=\frac{(a+b x) \left (a^2+2 a b x+b^2 x^2\right )^p \, _2F_1\left (1,1+2 p;2 (1+p);-\frac{e (a+b x)}{b d-a e}\right )}{(b d-a e) (1+2 p)}\\ \end{align*}
Mathematica [A] time = 0.0169132, size = 62, normalized size = 0.87 \[ -\frac{(a+b x) \left ((a+b x)^2\right )^p \, _2F_1\left (1,2 p+1;2 p+2;\frac{e (a+b x)}{a e-b d}\right )}{(2 p+1) (a e-b d)} \]
Antiderivative was successfully verified.
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Maple [F] time = 1.215, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ({b}^{2}{x}^{2}+2\,abx+{a}^{2} \right ) ^{p}}{ex+d}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{p}}{e x + d}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{p}}{e x + d}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (\left (a + b x\right )^{2}\right )^{p}}{d + e x}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{p}}{e x + d}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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